Three girls used the same number of small pebbles to make necklaces. Mary used
35 of her small pebbles, Min used
23 of hers and Linda used
34 of hers. They had a total of 81 small pebbles at first. How many small pebbles did each girl use?
Make the numerators the same.
LCM of 3, 2 and 3 = 6
35 Mary's small pebbles =
23 Min's small pebbles =
34 Linda's small pebbles
3x25x2 Mary's small pebbles =
2x33x3 Min's small pebbles =
3x24x2 Linda's small pebbles
610 Mary's small pebbles =
69 Min's small pebbles =
68 Linda's small pebbles
| |
Mary |
Min |
Linda |
| Before |
10 u |
9 u |
8 u |
| Change |
- 6 u |
- 6 u |
- 6 u |
| After |
4 u |
3 u |
2 u |
Total number of small pebbles at first
= 10 u + 9 u + 8 u
= 27 u
27 u = 81
1 u = 81 ÷ 27 = 3
Number of small pebbles that each girl used
= 6 u
= 6 x 3
= 18
Answer(s): 18
