PSLEShiyun made some croissants to sell.
34 of them were lotus paste croissants and the rest were kaya croissants. After selling 343 kaya croissants and
56 of the lotus paste croissants, she had
15 of the croissants left. How many croissants did Shiyun sell?
|
Lotus paste croissants |
Kaya croissants |
Total |
Comparing lotus paste croissants and kaya croissants at first |
3x2 |
1x2 |
4x2
|
Before |
6x1 |
|
|
Change |
- 5x1
|
- 343 |
|
After |
1x1
|
|
|
|
Lotus paste croissants |
Kaya croissants |
Total |
Before |
6 u |
2 u |
8 u
|
Change |
- 5 u
|
- 343 |
|
After
|
1 u
|
2 u - 343
|
15 x 8 u = 135 u |
The number of lotus paste croissants at first is repeated. Make the number of lotus paste croissants at first the same. LCM of 3 and 6 is 6.
Number of croissants left
= 1 u + 2 u - 343
= 3 u - 343
3 u - 343 = 1
35 u
3 u - 1
35 u = 343
1
25 u = 343
1 u = 343 ÷ 1
25 = 245
Total number of croissants that Shiyun sold
= 5 u + 343
= 5 x 245 + 343
= 1225 + 343
= 1568
Answer(s): 1568