PSLENicole made some croissants to sell.
34 of them were beef croissants and the rest were chocolate croissants. After selling 115 chocolate croissants and
56 of the beef croissants, she had
16 of the croissants left. How many croissants did Nicole sell?
|
Beef croissants |
Chocolate croissants |
Total |
Comparing beef croissants and chocolate croissants at first |
3x2 |
1x2 |
4x2
|
Before |
6x1 |
|
|
Change |
- 5x1
|
- 115 |
|
After |
1x1
|
|
|
|
Beef croissants |
Chocolate croissants |
Total |
Before |
6 u |
2 u |
8 u
|
Change |
- 5 u
|
- 115 |
|
After
|
1 u
|
2 u - 115
|
16 x 8 u = 113 u |
The number of beef croissants at first is repeated. Make the number of beef croissants at first the same. LCM of 3 and 6 is 6.
Number of croissants left
= 1 u + 2 u - 115
= 3 u - 115
3 u - 115 = 1
13 u
3 u - 1
13 u = 115
1
23 u = 115
1 u = 115 ÷ 1
23 = 69
Total number of croissants that Nicole sold
= 5 u + 115
= 5 x 69 + 115
= 345 + 115
= 460
Answer(s): 460