PSLESabrina made some buns to sell.
34 of them were chocolate buns and the rest were kaya buns. After selling 378 kaya buns and
56 of the chocolate buns, she had
15 of the buns left. How many buns did Sabrina sell?
|
Chocolate buns |
Kaya buns |
Total |
Comparing chocolate buns and kaya buns at first |
3x2 |
1x2 |
4x2
|
Before |
6x1 |
|
|
Change |
- 5x1
|
- 378 |
|
After |
1x1
|
|
|
|
Chocolate buns |
Kaya buns |
Total |
Before |
6 u |
2 u |
8 u
|
Change |
- 5 u
|
- 378 |
|
After
|
1 u
|
2 u - 378
|
15 x 8 u = 135 u |
The number of chocolate buns at first is repeated. Make the number of chocolate buns at first the same. LCM of 3 and 6 is 6.
Number of buns left
= 1 u + 2 u - 378
= 3 u - 378
3 u - 378 = 1
35 u
3 u - 1
35 u = 378
1
25 u = 378
1 u = 378 ÷ 1
25 = 270
Total number of buns that Sabrina sold
= 5 u + 378
= 5 x 270 + 378
= 1350 + 378
= 1728
Answer(s): 1728