PSLEIvory made some croissants to sell.
34 of them were chocolate croissants and the rest were chicken croissants. After selling 105 chicken croissants and
56 of the chocolate croissants, she had
16 of the croissants left. How many croissants did Ivory sell?
|
Chocolate croissants |
Chicken croissants |
Total |
Comparing chocolate croissants and chicken croissants at first |
3x2 |
1x2 |
4x2
|
Before |
6x1 |
|
|
Change |
- 5x1
|
- 105 |
|
After |
1x1
|
|
|
|
Chocolate croissants |
Chicken croissants |
Total |
Before |
6 u |
2 u |
8 u
|
Change |
- 5 u
|
- 105 |
|
After
|
1 u
|
2 u - 105
|
16 x 8 u = 113 u |
The number of chocolate croissants at first is repeated. Make the number of chocolate croissants at first the same. LCM of 3 and 6 is 6.
Number of croissants left
= 1 u + 2 u - 105
= 3 u - 105
3 u - 105 = 1
13 u
3 u - 1
13 u = 105
1
23 u = 105
1 u = 105 ÷ 1
23 = 63
Total number of croissants that Ivory sold
= 5 u + 105
= 5 x 63 + 105
= 315 + 105
= 420
Answer(s): 420