PSLEMarion made some sandwiches to sell.
34 of them were beef sandwiches and the rest were chocolate sandwiches. After selling 360 chocolate sandwiches and
56 of the beef sandwiches, she had
16 of the sandwiches left. How many sandwiches did Marion sell?
|
Beef sandwiches |
Chocolate sandwiches |
Total |
Comparing beef sandwiches and chocolate sandwiches at first |
3x2 |
1x2 |
4x2
|
Before |
6x1 |
|
|
Change |
- 5x1
|
- 360 |
|
After |
1x1
|
|
|
|
Beef sandwiches |
Chocolate sandwiches |
Total |
Before |
6 u |
2 u |
8 u
|
Change |
- 5 u
|
- 360 |
|
After
|
1 u
|
2 u - 360
|
16 x 8 u = 113 u |
The number of beef sandwiches at first is repeated. Make the number of beef sandwiches at first the same. LCM of 3 and 6 is 6.
Number of sandwiches left
= 1 u + 2 u - 360
= 3 u - 360
3 u - 360 = 1
13 u
3 u - 1
13 u = 360
1
23 u = 360
1 u = 360 ÷ 1
23 = 216
Total number of sandwiches that Marion sold
= 5 u + 360
= 5 x 216 + 360
= 1080 + 360
= 1440
Answer(s): 1440