PSLEPenelope made some croissants to sell.
34 of them were chicken croissants and the rest were sardine croissants. After selling 345 sardine croissants and
56 of the chicken croissants, she had
16 of the croissants left. How many croissants did Penelope sell?
|
Chicken croissants |
Sardine croissants |
Total |
Comparing chicken croissants and sardine croissants at first |
3x2 |
1x2 |
4x2
|
Before |
6x1 |
|
|
Change |
- 5x1
|
- 345 |
|
After |
1x1
|
|
|
|
Chicken croissants |
Sardine croissants |
Total |
Before |
6 u |
2 u |
8 u
|
Change |
- 5 u
|
- 345 |
|
After
|
1 u
|
2 u - 345
|
16 x 8 u = 113 u |
The number of chicken croissants at first is repeated. Make the number of chicken croissants at first the same. LCM of 3 and 6 is 6.
Number of croissants left
= 1 u + 2 u - 345
= 3 u - 345
3 u - 345 = 1
13 u
3 u - 1
13 u = 345
1
23 u = 345
1 u = 345 ÷ 1
23 = 207
Total number of croissants that Penelope sold
= 5 u + 345
= 5 x 207 + 345
= 1035 + 345
= 1380
Answer(s): 1380