PSLETina made some croissants to sell.
34 of them were chocolate croissants and the rest were chicken croissants. After selling 126 chicken croissants and
56 of the chocolate croissants, she had
15 of the croissants left. How many croissants did Tina sell?
|
Chocolate croissants |
Chicken croissants |
Total |
Comparing chocolate croissants and chicken croissants at first |
3x2 |
1x2 |
4x2
|
Before |
6x1 |
|
|
Change |
- 5x1
|
- 126 |
|
After |
1x1
|
|
|
|
Chocolate croissants |
Chicken croissants |
Total |
Before |
6 u |
2 u |
8 u
|
Change |
- 5 u
|
- 126 |
|
After
|
1 u
|
2 u - 126
|
15 x 8 u = 135 u |
The number of chocolate croissants at first is repeated. Make the number of chocolate croissants at first the same. LCM of 3 and 6 is 6.
Number of croissants left
= 1 u + 2 u - 126
= 3 u - 126
3 u - 126 = 1
35 u
3 u - 1
35 u = 126
1
25 u = 126
1 u = 126 ÷ 1
25 = 90
Total number of croissants that Tina sold
= 5 u + 126
= 5 x 90 + 126
= 450 + 126
= 576
Answer(s): 576