There were 10 more boys than girls in the computer lab. Excluding 8 girls, the number of girls was
23 of the number of boys. When another 4 boys joined, what fraction of the students were boys in the end? Give your answer in its simplest form.
|
Boys |
Girls |
Comparing boys and girls at first |
10 more |
|
Before |
3 u |
2 u + 8 |
Change |
+ 4 |
|
After |
3 u + 4 |
2 u + 8 |
Number of boys at first was 10 more than the number of girls. If another 10 girls entered the computer lab at first, the number of boys and girls at first would be the same.
3 u = 2 u + 8 + 10
3 u - 2 u = 8 + 10
1 u = 18
Total number of boys in the end
= 3 u + 4
= 3 x 18 + 4
= 54 + 4
= 58
Total number of students in the end
= 3 u + 4 + 2 u + 8
= 5 u + 12
= 5 x 18 + 12
= 102
Fraction of the students who were boys in the end
=
58102 =
2951 Answer(s):
2951