There were 6 more boys than girls in the computer lab. Excluding 10 girls, the number of girls was
45 of the number of boys. When another 8 boys joined, what fraction of the students were boys in the end? Give your answer in its simplest form.
|
Boys |
Girls |
Comparing boys and girls at first |
6 more |
|
Before |
5 u |
4 u + 10 |
Change |
+ 8 |
|
After |
5 u + 8 |
4 u + 10 |
Number of boys at first was 6 more than the number of girls. If another 6 girls entered the computer lab at first, the number of boys and girls at first would be the same.
5 u = 4 u + 10 + 6
5 u - 4 u = 10 + 6
1 u = 16
Total number of boys in the end
= 5 u + 8
= 5 x 16 + 8
= 80 + 8
= 88
Total number of students in the end
= 5 u + 8 + 4 u + 10
= 9 u + 18
= 9 x 16 + 18
= 162
Fraction of the students who were boys in the end
=
88162 =
4481 Answer(s):
4481