There were 104 pomegranates and chikoos altogether. After
56 of the pomegranates and half of the chikoos were given away, there were a total of 20 pomegranates and chikoos left. What fraction of the fruits were chikoos at first? Give your answer in its simplest form.
| |
Pomegranates |
Chikoos |
Total |
| Before |
6 u |
2 p |
104 |
| Change |
- 5 u |
- 1 p |
- 84 |
| After |
1 u |
1 p |
20 |
Number of pomegranates and chikoos given away
= 104 - 20
= 84
5 u + 1 p = 84
1 p = 84 - 5 u --- (1)
1 u + 1 p = 20
1 p = 20 - 1 u --- (2)
(2) = (1)
20 - 1 u = 84 - 5 u
5 u - 1 u = 84 - 20
4 u = 64
1 u = 64 ÷ 4 = 16
Number of pomegranates at first
= 6 u
= 6 x 16
= 96
Number of chikoos at first
= 104 - 96
= 8
Fraction of the fruits that were chikoos at first
=
8104 =
113 Answer(s):
113 
