There were 126 grapefruits and chikoos altogether. After
45 of the grapefruits and half of the chikoos were thrown away, there were a total of 45 grapefruits and chikoos left. What fraction of the fruits were grapefruits at first? Give your answer in its simplest form.
| |
Grapefruits |
Chikoos |
Total |
| Before |
5 u |
2 p |
126 |
| Change |
- 4 u |
- 1 p |
- 81 |
| After |
1 u |
1 p |
45 |
Number of grapefruits and chikoos thrown away
= 126 - 45
= 81
4 u + 1 p = 81
1 p = 81 - 4 u --- (1)
1 u + 1 p = 45
1 p = 45 - 1 u --- (2)
(2) = (1)
45 - 1 u = 81 - 4 u
4 u - 1 u = 81 - 45
3 u = 36
1 u = 36 ÷ 3 = 12
Number of grapefruits at first
= 5 u
= 5 x 12
= 60
Fraction of the fruits that were grapefruits at first
=
60126 =
1021 Answer(s):
1021 
