There were 132 peaches and kiwis altogether. After
67 of the peaches and half of the kiwis were thrown away, there were a total of 46 peaches and kiwis left. What fraction of the fruits were kiwis at first? Give your answer in its simplest form.
| |
Peaches |
Kiwis |
Total |
| Before |
7 u |
2 p |
132 |
| Change |
- 6 u |
- 1 p |
- 86 |
| After |
1 u |
1 p |
46 |
Number of peaches and kiwis thrown away
= 132 - 46
= 86
6 u + 1 p = 86
1 p = 86 - 6 u --- (1)
1 u + 1 p = 46
1 p = 46 - 1 u --- (2)
(2) = (1)
46 - 1 u = 86 - 6 u
6 u - 1 u = 86 - 46
5 u = 40
1 u = 40 ÷ 5 = 8
Number of peaches at first
= 7 u
= 7 x 8
= 56
Number of kiwis at first
= 132 - 56
= 76
Fraction of the fruits that were kiwis at first
=
76132 =
1933 Answer(s):
1933 
