There were 122 guavas and lemons altogether. After
56 of the guavas and half of the lemons were thrown away, there were a total of 39 guavas and lemons left. What fraction of the fruits were lemons at first? Give your answer in its simplest form.
| |
Guavas |
Lemons |
Total |
| Before |
6 u |
2 p |
122 |
| Change |
- 5 u |
- 1 p |
- 83 |
| After |
1 u |
1 p |
39 |
Number of guavas and lemons thrown away
= 122 - 39
= 83
5 u + 1 p = 83
1 p = 83 - 5 u --- (1)
1 u + 1 p = 39
1 p = 39 - 1 u --- (2)
(2) = (1)
39 - 1 u = 83 - 5 u
5 u - 1 u = 83 - 39
4 u = 44
1 u = 44 ÷ 4 = 11
Number of guavas at first
= 6 u
= 6 x 11
= 66
Number of lemons at first
= 122 - 66
= 56
Fraction of the fruits that were lemons at first
=
56122 =
2861 Answer(s):
2861 
