There were 112 lemons and pears altogether. After
34 of the lemons and half of the pears were thrown away, there were a total of 38 lemons and pears left. What fraction of the fruits were pears at first? Give your answer in its simplest form.
| |
Lemons |
Pears |
Total |
| Before |
4 u |
2 p |
112 |
| Change |
- 3 u |
- 1 p |
- 74 |
| After |
1 u |
1 p |
38 |
Number of lemons and pears thrown away
= 112 - 38
= 74
3 u + 1 p = 74
1 p = 74 - 3 u --- (1)
1 u + 1 p = 38
1 p = 38 - 1 u --- (2)
(2) = (1)
38 - 1 u = 74 - 3 u
3 u - 1 u = 74 - 38
2 u = 36
1 u = 36 ÷ 2 = 18
Number of lemons at first
= 4 u
= 4 x 18
= 72
Number of pears at first
= 112 - 72
= 40
Fraction of the fruits that were pears at first
=
40112 =
514 Answer(s):
514 
