There were 90 pears and persimmons altogether. After
78 of the pears and half of the persimmons were thrown away, there were a total of 33 pears and persimmons left. What fraction of the fruits were persimmons at first? Give your answer in its simplest form.
| |
Pears |
Persimmons |
Total |
| Before |
8 u |
2 p |
90 |
| Change |
- 7 u |
- 1 p |
- 57 |
| After |
1 u |
1 p |
33 |
Number of pears and persimmons thrown away
= 90 - 33
= 57
7 u + 1 p = 57
1 p = 57 - 7 u --- (1)
1 u + 1 p = 33
1 p = 33 - 1 u --- (2)
(2) = (1)
33 - 1 u = 57 - 7 u
7 u - 1 u = 57 - 33
6 u = 24
1 u = 24 ÷ 6 = 4
Number of pears at first
= 8 u
= 8 x 4
= 32
Number of persimmons at first
= 90 - 32
= 58
Fraction of the fruits that were persimmons at first
=
5890 =
2945 Answer(s):
2945 
