There were 102 lemons and peaches altogether. After
34 of the lemons and half of the peaches were thrown away, there were a total of 44 lemons and peaches left. What fraction of the fruits were lemons at first? Give your answer in its simplest form.
| |
Lemons |
Peaches |
Total |
| Before |
4 u |
2 p |
102 |
| Change |
- 3 u |
- 1 p |
- 58 |
| After |
1 u |
1 p |
44 |
Number of lemons and peaches thrown away
= 102 - 44
= 58
3 u + 1 p = 58
1 p = 58 - 3 u --- (1)
1 u + 1 p = 44
1 p = 44 - 1 u --- (2)
(2) = (1)
44 - 1 u = 58 - 3 u
3 u - 1 u = 58 - 44
2 u = 14
1 u = 14 ÷ 2 = 7
Number of lemons at first
= 4 u
= 4 x 7
= 28
Fraction of the fruits that were lemons at first
=
28102 =
1451 Answer(s):
1451 
