There were 126 kiwis and peaches altogether. After
56 of the kiwis and half of the peaches were thrown away, there were a total of 29 kiwis and peaches left. What fraction of the fruits were peaches at first? Give your answer in its simplest form.
| |
Kiwis |
Peaches |
Total |
| Before |
6 u |
2 p |
126 |
| Change |
- 5 u |
- 1 p |
- 97 |
| After |
1 u |
1 p |
29 |
Number of kiwis and peaches thrown away
= 126 - 29
= 97
5 u + 1 p = 97
1 p = 97 - 5 u --- (1)
1 u + 1 p = 29
1 p = 29 - 1 u --- (2)
(2) = (1)
29 - 1 u = 97 - 5 u
5 u - 1 u = 97 - 29
4 u = 68
1 u = 68 ÷ 4 = 17
Number of kiwis at first
= 6 u
= 6 x 17
= 102
Number of peaches at first
= 126 - 102
= 24
Fraction of the fruits that were peaches at first
=
24126 =
421 Answer(s):
421 
