There were 98 kiwis and guavas altogether. After
56 of the kiwis and half of the guavas were thrown away, there were a total of 33 kiwis and guavas left. What fraction of the fruits were guavas at first? Give your answer in its simplest form.
| |
Kiwis |
Guavas |
Total |
| Before |
6 u |
2 p |
98 |
| Change |
- 5 u |
- 1 p |
- 65 |
| After |
1 u |
1 p |
33 |
Number of kiwis and guavas thrown away
= 98 - 33
= 65
5 u + 1 p = 65
1 p = 65 - 5 u --- (1)
1 u + 1 p = 33
1 p = 33 - 1 u --- (2)
(2) = (1)
33 - 1 u = 65 - 5 u
5 u - 1 u = 65 - 33
4 u = 32
1 u = 32 ÷ 4 = 8
Number of kiwis at first
= 6 u
= 6 x 8
= 48
Number of guavas at first
= 98 - 48
= 50
Fraction of the fruits that were guavas at first
=
5098 =
2549 Answer(s):
2549 
