There were 112 grapefruits and chikoos altogether. After
56 of the grapefruits and half of the chikoos were thrown away, there were a total of 26 grapefruits and chikoos left. What fraction of the fruits were chikoos at first? Give your answer in its simplest form.
| |
Grapefruits |
Chikoos |
Total |
| Before |
6 u |
2 p |
112 |
| Change |
- 5 u |
- 1 p |
- 86 |
| After |
1 u |
1 p |
26 |
Number of grapefruits and chikoos thrown away
= 112 - 26
= 86
5 u + 1 p = 86
1 p = 86 - 5 u --- (1)
1 u + 1 p = 26
1 p = 26 - 1 u --- (2)
(2) = (1)
26 - 1 u = 86 - 5 u
5 u - 1 u = 86 - 26
4 u = 60
1 u = 60 ÷ 4 = 15
Number of grapefruits at first
= 6 u
= 6 x 15
= 90
Number of chikoos at first
= 112 - 90
= 22
Fraction of the fruits that were chikoos at first
=
22112 =
1156 Answer(s):
1156 
