There were 124 chikoos and starfruits altogether. After
56 of the chikoos and half of the starfruits were sold, there were a total of 42 chikoos and starfruits left. What fraction of the fruits were starfruits at first? Give your answer in its simplest form.
| |
Chikoos |
Starfruits |
Total |
| Before |
6 u |
2 p |
124 |
| Change |
- 5 u |
- 1 p |
- 82 |
| After |
1 u |
1 p |
42 |
Number of chikoos and starfruits sold
= 124 - 42
= 82
5 u + 1 p = 82
1 p = 82 - 5 u --- (1)
1 u + 1 p = 42
1 p = 42 - 1 u --- (2)
(2) = (1)
42 - 1 u = 82 - 5 u
5 u - 1 u = 82 - 42
4 u = 40
1 u = 40 ÷ 4 = 10
Number of chikoos at first
= 6 u
= 6 x 10
= 60
Number of starfruits at first
= 124 - 60
= 64
Fraction of the fruits that were starfruits at first
=
64124 =
1631 Answer(s):
1631 
