There were 106 pears and persimmons altogether. After
56 of the pears and half of the persimmons were given away, there were a total of 23 pears and persimmons left. What fraction of the fruits were pears at first? Give your answer in its simplest form.
| |
Pears |
Persimmons |
Total |
| Before |
6 u |
2 p |
106 |
| Change |
- 5 u |
- 1 p |
- 83 |
| After |
1 u |
1 p |
23 |
Number of pears and persimmons given away
= 106 - 23
= 83
5 u + 1 p = 83
1 p = 83 - 5 u --- (1)
1 u + 1 p = 23
1 p = 23 - 1 u --- (2)
(2) = (1)
23 - 1 u = 83 - 5 u
5 u - 1 u = 83 - 23
4 u = 60
1 u = 60 ÷ 4 = 15
Number of pears at first
= 6 u
= 6 x 15
= 90
Fraction of the fruits that were pears at first
=
90106 =
4553 Answer(s):
4553 
