There were 90 chikoos and grapefruits altogether. After
78 of the chikoos and half of the grapefruits were given away, there were a total of 39 chikoos and grapefruits left. What fraction of the fruits were grapefruits at first? Give your answer in its simplest form.
| |
Chikoos |
Grapefruits |
Total |
| Before |
8 u |
2 p |
90 |
| Change |
- 7 u |
- 1 p |
- 51 |
| After |
1 u |
1 p |
39 |
Number of chikoos and grapefruits given away
= 90 - 39
= 51
7 u + 1 p = 51
1 p = 51 - 7 u --- (1)
1 u + 1 p = 39
1 p = 39 - 1 u --- (2)
(2) = (1)
39 - 1 u = 51 - 7 u
7 u - 1 u = 51 - 39
6 u = 12
1 u = 12 ÷ 6 = 2
Number of chikoos at first
= 8 u
= 8 x 2
= 16
Number of grapefruits at first
= 90 - 16
= 74
Fraction of the fruits that were grapefruits at first
=
7490 =
3745 Answer(s):
3745 
