There were 98 pomegranates and guavas altogether. After
34 of the pomegranates and half of the guavas were thrown away, there were a total of 40 pomegranates and guavas left. What fraction of the fruits were guavas at first? Give your answer in its simplest form.
| |
Pomegranates |
Guavas |
Total |
| Before |
4 u |
2 p |
98 |
| Change |
- 3 u |
- 1 p |
- 58 |
| After |
1 u |
1 p |
40 |
Number of pomegranates and guavas thrown away
= 98 - 40
= 58
3 u + 1 p = 58
1 p = 58 - 3 u --- (1)
1 u + 1 p = 40
1 p = 40 - 1 u --- (2)
(2) = (1)
40 - 1 u = 58 - 3 u
3 u - 1 u = 58 - 40
2 u = 18
1 u = 18 ÷ 2 = 9
Number of pomegranates at first
= 4 u
= 4 x 9
= 36
Number of guavas at first
= 98 - 36
= 62
Fraction of the fruits that were guavas at first
=
6298 =
3149 Answer(s):
3149 
