There were 90 grapefruits and chikoos altogether. After
34 of the grapefruits and half of the chikoos were sold, there were a total of 37 grapefruits and chikoos left. What fraction of the fruits were chikoos at first? Give your answer in its simplest form.
| |
Grapefruits |
Chikoos |
Total |
| Before |
4 u |
2 p |
90 |
| Change |
- 3 u |
- 1 p |
- 53 |
| After |
1 u |
1 p |
37 |
Number of grapefruits and chikoos sold
= 90 - 37
= 53
3 u + 1 p = 53
1 p = 53 - 3 u --- (1)
1 u + 1 p = 37
1 p = 37 - 1 u --- (2)
(2) = (1)
37 - 1 u = 53 - 3 u
3 u - 1 u = 53 - 37
2 u = 16
1 u = 16 ÷ 2 = 8
Number of grapefruits at first
= 4 u
= 4 x 8
= 32
Number of chikoos at first
= 90 - 32
= 58
Fraction of the fruits that were chikoos at first
=
5890 =
2945 Answer(s):
2945 
