There were 102 chikoos and peaches altogether. After
34 of the chikoos and half of the peaches were sold, there were a total of 36 chikoos and peaches left. What fraction of the fruits were chikoos at first? Give your answer in its simplest form.
| |
Chikoos |
Peaches |
Total |
| Before |
4 u |
2 p |
102 |
| Change |
- 3 u |
- 1 p |
- 66 |
| After |
1 u |
1 p |
36 |
Number of chikoos and peaches sold
= 102 - 36
= 66
3 u + 1 p = 66
1 p = 66 - 3 u --- (1)
1 u + 1 p = 36
1 p = 36 - 1 u --- (2)
(2) = (1)
36 - 1 u = 66 - 3 u
3 u - 1 u = 66 - 36
2 u = 30
1 u = 30 ÷ 2 = 15
Number of chikoos at first
= 4 u
= 4 x 15
= 60
Fraction of the fruits that were chikoos at first
=
60102 =
1017 Answer(s):
1017 
