There were 110 grapefruits and guavas altogether. After
67 of the grapefruits and half of the guavas were thrown away, there were a total of 50 grapefruits and guavas left. What fraction of the fruits were guavas at first? Give your answer in its simplest form.
| |
Grapefruits |
Guavas |
Total |
| Before |
7 u |
2 p |
110 |
| Change |
- 6 u |
- 1 p |
- 60 |
| After |
1 u |
1 p |
50 |
Number of grapefruits and guavas thrown away
= 110 - 50
= 60
6 u + 1 p = 60
1 p = 60 - 6 u --- (1)
1 u + 1 p = 50
1 p = 50 - 1 u --- (2)
(2) = (1)
50 - 1 u = 60 - 6 u
6 u - 1 u = 60 - 50
5 u = 10
1 u = 10 ÷ 5 = 2
Number of grapefruits at first
= 7 u
= 7 x 2
= 14
Number of guavas at first
= 110 - 14
= 96
Fraction of the fruits that were guavas at first
=
96110 =
4855 Answer(s):
4855 
