There were 112 kiwis and persimmons altogether. After
78 of the kiwis and half of the persimmons were thrown away, there were a total of 44 kiwis and persimmons left. What fraction of the fruits were persimmons at first? Give your answer in its simplest form.
| |
Kiwis |
Persimmons |
Total |
| Before |
8 u |
2 p |
112 |
| Change |
- 7 u |
- 1 p |
- 68 |
| After |
1 u |
1 p |
44 |
Number of kiwis and persimmons thrown away
= 112 - 44
= 68
7 u + 1 p = 68
1 p = 68 - 7 u --- (1)
1 u + 1 p = 44
1 p = 44 - 1 u --- (2)
(2) = (1)
44 - 1 u = 68 - 7 u
7 u - 1 u = 68 - 44
6 u = 24
1 u = 24 ÷ 6 = 4
Number of kiwis at first
= 8 u
= 8 x 4
= 32
Number of persimmons at first
= 112 - 32
= 80
Fraction of the fruits that were persimmons at first
=
80112 =
57 Answer(s):
57 
