There were 132 kiwis and chikoos altogether. After
34 of the kiwis and half of the chikoos were thrown away, there were a total of 41 kiwis and chikoos left. What fraction of the fruits were chikoos at first? Give your answer in its simplest form.
| |
Kiwis |
Chikoos |
Total |
| Before |
4 u |
2 p |
132 |
| Change |
- 3 u |
- 1 p |
- 91 |
| After |
1 u |
1 p |
41 |
Number of kiwis and chikoos thrown away
= 132 - 41
= 91
3 u + 1 p = 91
1 p = 91 - 3 u --- (1)
1 u + 1 p = 41
1 p = 41 - 1 u --- (2)
(2) = (1)
41 - 1 u = 91 - 3 u
3 u - 1 u = 91 - 41
2 u = 50
1 u = 50 ÷ 2 = 25
Number of kiwis at first
= 4 u
= 4 x 25
= 100
Number of chikoos at first
= 132 - 100
= 32
Fraction of the fruits that were chikoos at first
=
32132 =
833 Answer(s):
833 
