There were 104 chikoos and pomegranates altogether. After
34 of the chikoos and half of the pomegranates were given away, there were a total of 41 chikoos and pomegranates left. What fraction of the fruits were chikoos at first? Give your answer in its simplest form.
|
Chikoos |
Pomegranates |
Total |
Before |
4 u |
2 p |
104 |
Change |
- 3 u |
- 1 p |
- 63 |
After |
1 u |
1 p |
41 |
Number of chikoos and pomegranates given away
= 104 - 41
= 63
3 u + 1 p = 63
1 p = 63 - 3 u --- (1)
1 u + 1 p = 41
1 p = 41 - 1 u --- (2)
(2) = (1)
41 - 1 u = 63 - 3 u
3 u - 1 u = 63 - 41
2 u = 22
1 u = 22 ÷ 2 = 11
Number of chikoos at first
= 4 u
= 4 x 11
= 44
Fraction of the fruits that were chikoos at first
=
44104 =
1126 Answer(s):
1126