There were 116 starfruits and chikoos altogether. After
56 of the starfruits and half of the chikoos were thrown away, there were a total of 32 starfruits and chikoos left. What fraction of the fruits were starfruits at first? Give your answer in its simplest form.
|
Starfruits |
Chikoos |
Total |
Before |
6 u |
2 p |
116 |
Change |
- 5 u |
- 1 p |
- 84 |
After |
1 u |
1 p |
32 |
Number of starfruits and chikoos thrown away
= 116 - 32
= 84
5 u + 1 p = 84
1 p = 84 - 5 u --- (1)
1 u + 1 p = 32
1 p = 32 - 1 u --- (2)
(2) = (1)
32 - 1 u = 84 - 5 u
5 u - 1 u = 84 - 32
4 u = 52
1 u = 52 ÷ 4 = 13
Number of starfruits at first
= 6 u
= 6 x 13
= 78
Fraction of the fruits that were starfruits at first
=
78116 =
3958 Answer(s):
3958