There were 105 persimmons and kiwis altogether. After
67 of the persimmons and half of the kiwis were given away, there were a total of 50 persimmons and kiwis left. What fraction of the fruits were kiwis at first? Give your answer in its simplest form.
| |
Persimmons |
Kiwis |
Total |
| Before |
7 u |
2 p |
105 |
| Change |
- 6 u |
- 1 p |
- 55 |
| After |
1 u |
1 p |
50 |
Number of persimmons and kiwis given away
= 105 - 50
= 55
6 u + 1 p = 55
1 p = 55 - 6 u --- (1)
1 u + 1 p = 50
1 p = 50 - 1 u --- (2)
(2) = (1)
50 - 1 u = 55 - 6 u
6 u - 1 u = 55 - 50
5 u = 5
1 u = 5 ÷ 5 = 1
Number of persimmons at first
= 7 u
= 7 x 1
= 7
Number of kiwis at first
= 105 - 7
= 98
Fraction of the fruits that were kiwis at first
=
98105 =
1415 Answer(s):
1415 
