There were 140 mangoes and chikoos altogether. After
67 of the mangoes and half of the chikoos were given away, there were a total of 40 mangoes and chikoos left. What fraction of the fruits were mangoes at first? Give your answer in its simplest form.
|
Mangoes |
Chikoos |
Total |
Before |
7 u |
2 p |
140 |
Change |
- 6 u |
- 1 p |
- 100 |
After |
1 u |
1 p |
40 |
Number of mangoes and chikoos given away
= 140 - 40
= 100
6 u + 1 p = 100
1 p = 100 - 6 u --- (1)
1 u + 1 p = 40
1 p = 40 - 1 u --- (2)
(2) = (1)
40 - 1 u = 100 - 6 u
6 u - 1 u = 100 - 40
5 u = 60
1 u = 60 ÷ 5 = 12
Number of mangoes at first
= 7 u
= 7 x 12
= 84
Fraction of the fruits that were mangoes at first
=
84140 =
35 Answer(s):
35