There were 106 peaches and lemons altogether. After
78 of the peaches and half of the lemons were given away, there were a total of 44 peaches and lemons left. What fraction of the fruits were lemons at first? Give your answer in its simplest form.
| |
Peaches |
Lemons |
Total |
| Before |
8 u |
2 p |
106 |
| Change |
- 7 u |
- 1 p |
- 62 |
| After |
1 u |
1 p |
44 |
Number of peaches and lemons given away
= 106 - 44
= 62
7 u + 1 p = 62
1 p = 62 - 7 u --- (1)
1 u + 1 p = 44
1 p = 44 - 1 u --- (2)
(2) = (1)
44 - 1 u = 62 - 7 u
7 u - 1 u = 62 - 44
6 u = 18
1 u = 18 ÷ 6 = 3
Number of peaches at first
= 8 u
= 8 x 3
= 24
Number of lemons at first
= 106 - 24
= 82
Fraction of the fruits that were lemons at first
=
82106 =
4153 Answer(s):
4153 
