There were 126 peaches and kiwis altogether. After
78 of the peaches and half of the kiwis were thrown away, there were a total of 39 peaches and kiwis left. What fraction of the fruits were peaches at first? Give your answer in its simplest form.
| |
Peaches |
Kiwis |
Total |
| Before |
8 u |
2 p |
126 |
| Change |
- 7 u |
- 1 p |
- 87 |
| After |
1 u |
1 p |
39 |
Number of peaches and kiwis thrown away
= 126 - 39
= 87
7 u + 1 p = 87
1 p = 87 - 7 u --- (1)
1 u + 1 p = 39
1 p = 39 - 1 u --- (2)
(2) = (1)
39 - 1 u = 87 - 7 u
7 u - 1 u = 87 - 39
6 u = 48
1 u = 48 ÷ 6 = 8
Number of peaches at first
= 8 u
= 8 x 8
= 64
Fraction of the fruits that were peaches at first
=
64126 =
3263 Answer(s):
3263 
