There were 94 kiwis and chikoos altogether. After
56 of the kiwis and half of the chikoos were thrown away, there were a total of 29 kiwis and chikoos left. What fraction of the fruits were chikoos at first? Give your answer in its simplest form.
| |
Kiwis |
Chikoos |
Total |
| Before |
6 u |
2 p |
94 |
| Change |
- 5 u |
- 1 p |
- 65 |
| After |
1 u |
1 p |
29 |
Number of kiwis and chikoos thrown away
= 94 - 29
= 65
5 u + 1 p = 65
1 p = 65 - 5 u --- (1)
1 u + 1 p = 29
1 p = 29 - 1 u --- (2)
(2) = (1)
29 - 1 u = 65 - 5 u
5 u - 1 u = 65 - 29
4 u = 36
1 u = 36 ÷ 4 = 9
Number of kiwis at first
= 6 u
= 6 x 9
= 54
Number of chikoos at first
= 94 - 54
= 40
Fraction of the fruits that were chikoos at first
=
4094 =
2047 Answer(s):
2047 
