There were 136 grapefruits and peaches altogether. After
67 of the grapefruits and half of the peaches were given away, there were a total of 43 grapefruits and peaches left. What fraction of the fruits were peaches at first? Give your answer in its simplest form.
| |
Grapefruits |
Peaches |
Total |
| Before |
7 u |
2 p |
136 |
| Change |
- 6 u |
- 1 p |
- 93 |
| After |
1 u |
1 p |
43 |
Number of grapefruits and peaches given away
= 136 - 43
= 93
6 u + 1 p = 93
1 p = 93 - 6 u --- (1)
1 u + 1 p = 43
1 p = 43 - 1 u --- (2)
(2) = (1)
43 - 1 u = 93 - 6 u
6 u - 1 u = 93 - 43
5 u = 50
1 u = 50 ÷ 5 = 10
Number of grapefruits at first
= 7 u
= 7 x 10
= 70
Number of peaches at first
= 136 - 70
= 66
Fraction of the fruits that were peaches at first
=
66136 =
3368 Answer(s):
3368 
