There were 102 grapefruits and lemons altogether. After
56 of the grapefruits and half of the lemons were thrown away, there were a total of 47 grapefruits and lemons left. What fraction of the fruits were lemons at first? Give your answer in its simplest form.
| |
Grapefruits |
Lemons |
Total |
| Before |
6 u |
2 p |
102 |
| Change |
- 5 u |
- 1 p |
- 55 |
| After |
1 u |
1 p |
47 |
Number of grapefruits and lemons thrown away
= 102 - 47
= 55
5 u + 1 p = 55
1 p = 55 - 5 u --- (1)
1 u + 1 p = 47
1 p = 47 - 1 u --- (2)
(2) = (1)
47 - 1 u = 55 - 5 u
5 u - 1 u = 55 - 47
4 u = 8
1 u = 8 ÷ 4 = 2
Number of grapefruits at first
= 6 u
= 6 x 2
= 12
Number of lemons at first
= 102 - 12
= 90
Fraction of the fruits that were lemons at first
=
90102 =
1517 Answer(s):
1517 
