Jaslyn had four times the number of toy bricks as Pierre. Jaslyn used all her bricks to build 8 identical ships. Pierre used all his bricks to build 4 identical ships. Jaslyn used 9 more bricks than Pierre for each ship. How many bricks did Pierre have?
|
Jaslyn |
Pierre |
Number |
8 |
4 |
Value |
1 u + 9 |
1 u |
Total value |
8 u + 72 |
4 u |
Number of toy bricks that Pierre used for each ship = 1 u
Number of toy bricks that Jaslyn used for each ship = 1 u + 9
Number of toy bricks that Pierre had
= 4 x 1 u
= 4 u
Number of toy bricks that Jaslyn had
= 8 x (1 u + 9)
= 8 u + 72
Jaslyn had four times the number of toy bricks as Pierre.
4 x 4 u = 8 u + 72
16 u = 8 u + 72
16 u - 8 u = 72
8 u = 72
1 u = 72 ÷ 8 = 9
Number of bricks that Pierre had
= 4 u
= 4 x 9
= 36
Answer(s): 36