Tina had thrice the number of toy bricks as Pierre. Tina used all her bricks to build 8 identical ships. Pierre used all his bricks to build 4 identical ships. Tina used 9 more bricks than Pierre for each ship. How many bricks did Pierre have?
| |
Tina |
Pierre |
| Number |
8 |
4 |
| Value |
1 u + 9 |
1 u |
| Total value |
8 u + 72 |
4 u |
Number of toy bricks that Pierre used for each ship = 1 u
Number of toy bricks that Tina used for each ship = 1 u + 9
Number of toy bricks that Pierre had
= 4 x 1 u
= 4 u
Number of toy bricks that Tina had
= 8 x (1 u + 9)
= 8 u + 72
Tina had thrice the number of toy bricks as Pierre.
3 x 4 u = 8 u + 72
12 u = 8 u + 72
12 u - 8 u = 72
4 u = 72
1 u = 72 ÷ 4 = 18
Number of bricks that Pierre had
= 4 u
= 4 x 18
= 72
Answer(s): 72
