PSLEHoward had a number of necklaces for sale. He sold a total of 528 necklaces on Monday and Tuesday. On Wednesday, he sold
14 of the remainder. He was left with 9% of the necklaces he had at first. How many necklaces did he have at first?
Monday |
Tuesday |
Remainder |
528 |
Wednesday |
Left |
|
|
1 u |
3 u |
88%
|
3% |
9% |
Fraction of the remainder left
= 1 -
14 =
34Percent of total necklaces sold on Wednesday
= 9% ÷ 3
= 3%
Percent of total necklaces sold on Monday and Tuesday
= 100% - 9% - 3%
= 88%
88% = 528
1% = 528 ÷ 88 = 6
Total number of necklaces at first
= 100%
= 100 x 6
= 600
Answer(s): 600