PSLECole had a number of bracelets for sale. He sold a total of 480 bracelets on Thursday and Friday. On Saturday, he sold
15 of the remainder. He was left with 16% of the bracelets he had at first. How many bracelets did he have at first?
Thursday |
Friday |
Remainder |
480 |
Saturday |
Left |
|
|
1 u |
4 u |
80%
|
4% |
16% |
Fraction of the remainder left
= 1 -
15 =
45Percent of total bracelets sold on Saturday
= 16% ÷ 4
= 4%
Percent of total bracelets sold on Thursday and Friday
= 100% - 16% - 4%
= 80%
80% = 480
1% = 480 ÷ 80 = 6
Total number of bracelets at first
= 100%
= 100 x 6
= 600
Answer(s): 600