PSLEOliver had a number of necklaces for sale. He sold a total of 900 necklaces on Tuesday and Wednesday. On Thursday, he sold
15 of the remainder. He was left with 8% of the necklaces he had at first. How many necklaces did he have at first?
Tuesday |
Wednesday |
Remainder |
900 |
Thursday |
Left |
|
|
1 u |
4 u |
90%
|
2% |
8% |
Fraction of the remainder left
= 1 -
15 =
45Percent of total necklaces sold on Thursday
= 8% ÷ 4
= 2%
Percent of total necklaces sold on Tuesday and Wednesday
= 100% - 8% - 2%
= 90%
90% = 900
1% = 900 ÷ 90 = 10
Total number of necklaces at first
= 100%
= 100 x 10
= 1000
Answer(s): 1000