PSLEKen had a number of bracelets for sale. He sold a total of 360 bracelets on Wednesday and Thursday. On Friday, he sold
15 of the remainder. He was left with 8% of the bracelets he had at first. How many bracelets did he have at first?
Wednesday |
Thursday |
Remainder |
360 |
Friday |
Left |
|
|
1 u |
4 u |
90%
|
2% |
8% |
Fraction of the remainder left
= 1 -
15 =
45Percent of total bracelets sold on Friday
= 8% ÷ 4
= 2%
Percent of total bracelets sold on Wednesday and Thursday
= 100% - 8% - 2%
= 90%
90% = 360
1% = 360 ÷ 90 = 4
Total number of bracelets at first
= 100%
= 100 x 4
= 400
Answer(s): 400