PSLEFred had a number of bracelets for sale. He sold a total of 704 bracelets on Friday and Saturday. On Sunday, he sold
14 of the remainder. He was left with 9% of the bracelets he had at first. How many bracelets did he have at first?
Friday |
Saturday |
Remainder |
704 |
Sunday |
Left |
|
|
1 u |
3 u |
88%
|
3% |
9% |
Fraction of the remainder left
= 1 -
14 =
34Percent of total bracelets sold on Sunday
= 9% ÷ 3
= 3%
Percent of total bracelets sold on Friday and Saturday
= 100% - 9% - 3%
= 88%
88% = 704
1% = 704 ÷ 88 = 8
Total number of bracelets at first
= 100%
= 100 x 8
= 800
Answer(s): 800