PSLEPaul had a number of bracelets for sale. He sold a total of 840 bracelets on Sunday and Monday. On Tuesday, he sold
14 of the remainder. He was left with 12% of the bracelets he had at first. How many bracelets did he have at first?
Sunday |
Monday |
Remainder |
840 |
Tuesday |
Left |
|
|
1 u |
3 u |
84%
|
4% |
12% |
Fraction of the remainder left
= 1 -
14 =
34Percent of total bracelets sold on Tuesday
= 12% ÷ 3
= 4%
Percent of total bracelets sold on Sunday and Monday
= 100% - 12% - 4%
= 84%
84% = 840
1% = 840 ÷ 84 = 10
Total number of bracelets at first
= 100%
= 100 x 10
= 1000
Answer(s): 1000