PSLEValen had a number of necklaces for sale. He sold a total of 440 necklaces on Tuesday and Wednesday. On Thursday, he sold
14 of the remainder. He was left with 9% of the necklaces he had at first. How many necklaces did he have at first?
Tuesday |
Wednesday |
Remainder |
440 |
Thursday |
Left |
|
|
1 u |
3 u |
88%
|
3% |
9% |
Fraction of the remainder left
= 1 -
14 =
34Percent of total necklaces sold on Thursday
= 9% ÷ 3
= 3%
Percent of total necklaces sold on Tuesday and Wednesday
= 100% - 9% - 3%
= 88%
88% = 440
1% = 440 ÷ 88 = 5
Total number of necklaces at first
= 100%
= 100 x 5
= 500
Answer(s): 500