PSLETim had a number of rings for sale. He sold a total of 828 rings on Thursday and Friday. On Saturday, he sold
14 of the remainder. He was left with 6% of the rings he had at first. How many rings did he have at first?
Thursday |
Friday |
Remainder |
828 |
Saturday |
Left |
|
|
1 u |
3 u |
92%
|
2% |
6% |
Fraction of the remainder left
= 1 -
14 =
34Percent of total rings sold on Saturday
= 6% ÷ 3
= 2%
Percent of total rings sold on Thursday and Friday
= 100% - 6% - 2%
= 92%
92% = 828
1% = 828 ÷ 92 = 9
Total number of rings at first
= 100%
= 100 x 9
= 900
Answer(s): 900