PSLEHenry had a number of bracelets for sale. He sold a total of 340 bracelets on Sunday and Monday. On Tuesday, he sold
15 of the remainder. He was left with 12% of the bracelets he had at first. How many bracelets did he have at first?
Sunday |
Monday |
Remainder |
340 |
Tuesday |
Left |
|
|
1 u |
4 u |
85%
|
3% |
12% |
Fraction of the remainder left
= 1 -
15 =
45Percent of total bracelets sold on Tuesday
= 12% ÷ 4
= 3%
Percent of total bracelets sold on Sunday and Monday
= 100% - 12% - 3%
= 85%
85% = 340
1% = 340 ÷ 85 = 4
Total number of bracelets at first
= 100%
= 100 x 4
= 400
Answer(s): 400