PSLEFabian had a number of rings for sale. He sold a total of 900 rings on Friday and Saturday. On Sunday, he sold
15 of the remainder. He was left with 8% of the rings he had at first. How many rings did he have at first?
Friday |
Saturday |
Remainder |
900 |
Sunday |
Left |
|
|
1 u |
4 u |
90%
|
2% |
8% |
Fraction of the remainder left
= 1 -
15 =
45Percent of total rings sold on Sunday
= 8% ÷ 4
= 2%
Percent of total rings sold on Friday and Saturday
= 100% - 8% - 2%
= 90%
90% = 900
1% = 900 ÷ 90 = 10
Total number of rings at first
= 100%
= 100 x 10
= 1000
Answer(s): 1000